2.9 由下列条件求解析函数 (z)=u+iv.-|||-(1) =(x-y)((x)^2+4xy+(y)^2);-|||-(2) =2xy+3x;-|||-(3) u=2(x-1)y (0)=-i;-|||-(4) =(e)^x(xcos y-ysin y) , (0)=0.

29.由下列各已知调和函数求解析函数 f(z)=u+iv =-|||-(1) =(x-y)((x)^2+4xy+(y)^2) ;-|||-(2) =dfrac

30.由下列各已知调和函数求解析函数f(z)=u+iv.1)u=(x-y)(x²+4xy+y²);2v=(y)/(x^2)+y^(2),f(2)=0;30.由下

九、设 f(z)=u+iv 解析,且 -v=(x-y)((x)^2+4xy+(y)^2), 求f(z)·

证明u(x,y)=(x-y)(x^2+4 xy+y^2)u(x,y)=(x-y)(x^2+4 xy+y^2)u(x,y)=(x-y)(x^2+4 xy+y^2)

16.分别由下列条件求解析函数 f(z)=u+iv 。-|||-(1) =(x)^2+xy-(y)^2 ,-|||-f(i)=-1+i ;-|||-(2) =(

函数 f(z)=u+iv 是一个解析函数，且 u+v=x^3-y^3+3x^2y-3xy^2-2x-2y，求 f(z)=u+iv.21. 函数 $f(z)=u+

2.4.10 证明下面u或v为调和函数，并求解析函数f(z)=u+iv:(a)u=x³-3xy²; (b)u=x²-y²+2x;(c)u=(x)/(x^2)+

(5)z=lntan(x)/(y); (6)z=(1+xy)^y; (7)u=x^(y)/(2); (8)u=arctan(x-y)^2.(5)$z=\ln\t

下列函数何处可导？何处解析？(1) f(z) = xy^2 + ix^2 y;(3) f(z) = x^3 - 3xy^2 + i(3x^2 y - y^3);

(3)(x^2+2xy-y^2)dx+(y^2+2xy-x^2)dy=0,y|_(x=1)=1;(3)$(x^{2}+2xy-y^{2})dx+(y^{2}+2