设 M=int_(-(pi)/(2))^(pi)/(2) (sin x)/(1+x^2) cos^4 x dx，N=int_(-(pi)/(2))^(pi)/(
(15)int_(-(pi)/(2))^(pi)/(2)sqrt(cos x-cos^3)xdx;(15)$\int_{-\frac{\pi}{2}}^{\fr
(d)/(dx)int_(sin x)^cos x cos(pi t^2) , dt = ( ). $\frac{d}{dx}\int_{\sin x}^{\c
int_(0)^pi/2(cos x+2)dx=( ).A. $\pi+1$B. $\pi$C. 2D. $\pi/2+2$
计算定积分：int_(0)^dfrac(pi {2)}(|sin x-cos x|{d)x}．计算定积分：$\int_{0}^{\dfrac{\pi }{2}}
(int )_(-dfrac {pi )(2)}^dfrac (pi {2)}dfrac (|x|sin x)(1+{cos )^3x}dx=(int )_(-
【例10】已知f(x)连续，int_(0)^xtf(x-t)dt=1-cos x，求int_(0)^(pi)/(2)f(x)dx的值.【例10】已知f(x)连续
(4)int_((pi)/(4))^(pi)/(3)(x)/(sin^2)xdx;(4)$\int_{\frac{\pi}{4}}^{\frac{\pi}{3}
46.【2020河南】计算定积分int_(0)^(pi)/(4)(1)/(cos^2)x+3dx.46.【2020河南】计算定积分$\int_{0}^{\fra
(int )_(-dfrac {pi )(2)}^dfrac (pi {2)}((cos )^2x+dfrac (xcos x)(1+{cos )^2x})dx