例3 设椭圆 :dfrac ({x)^2}({a)^2}+dfrac ({y)^2}({b)^2}=1(agt bgt 0) 的左、-|||-右焦点分别为F1,
与双曲线(({x^2)})/(2)-(y^2)=1有相同渐近线,且与椭圆(({y^2)})/(4)+(x^2)=1有共同焦点的双曲线方程是( )A. ${x^2
1.设f,φ是C^(2)类类函数, =yf(dfrac (x)(y))+xvarphi (dfrac (y)(x)), 求:(1) a2/ey; (2) dfr
设F1,F2分别是椭圆 :(x)^2+dfrac ({y)^2}({b)^2}=1(0lt -|||-lt 1) 的左、右焦点,过点F1的直线交椭圆E 于 A
设双曲线C:((x)^2)/((a)^2)-((y)^2)/((b)^2)=1(a>0,b>0)的左、右焦点分别为F1,F2,过F2作平行于y轴的直线交C于A,
设 =dfrac (y)(f({x)^2-(y)^2)} ,其中f(u)为可导函数,验证-|||-.dfrac (1)(x)dfrac (dz)(partial
设L为椭圆dfrac ({x)^2}(2)+dfrac ({y)^2}(3)=1,其周长为a,则dfrac ({x)^2}(2)+dfrac ({y)^2}(3
3.设 =dfrac (y)(f({x)^2-(y)^2)} ,其中f为可微函数,验证-|||-dfrac (1)(x)dfrac (partial z)(pa
设C是椭圆 dfrac ({x)^2}(3)+dfrac ({y)^2}(2)=1, 其周长为L,设C是椭圆 dfrac ({x)^2}(3)+dfrac ({
7.设 =dfrac (y)(f({x)^2-(y)^2)} 其中f为可导函数,验证: dfrac (1)(x)dfrac (partial z)(partia