5.试判断下列函数的可微性和解析性:-|||-(1) (z)=x(y)^2+i(x)^2y ;-|||-(2) (z)=(x)^2+i(y)^2 ;-|||-(3) (z)=2(x)^3+3i(y)^3 ;-|||-(4) (z)=(x)^3-3x(y)^2+i(3(x)^2y-(y)^3) -

.试判断函数f(z)=x^3-3xy^2+i(3x^2y-y^3) 的可微性和解析性..试判断函数f(z)=x^3-3xy^2+i(3x^2y-y^3) 的可微

2.下列函数何处可导?何处解析?-|||-(1) (z)=(x)^2-iy ;-|||-(2) (z)=2(x)^3+3(y)^3i;-|||-(3) (z)=

4.下列函数在何处可导?何处解析?在可导点处求出其导数.-|||-(1) (z)=x(y)^2+i(x)^2y ;-|||-(2) (z)=(x)^2-iy ;

下列函数何处可导？何处解析？(1) f(z) = xy^2 + ix^2 y;(3) f(z) = x^3 - 3xy^2 + i(3x^2 y - y^3);

函数(z)=(x)^2+(y)^2i ( ).A.仅在(z)=(x)^2+(y)^2i上解析;B.在除(z)=(x)^2+(y)^2i之外的复平面上

设函数(x,y,z)=2(x)^3y-3(y)^2z在点(x,y,z)=2(x)^3y-3(y)^2z处梯度的模为(x,y,z)=2(x)^3y-3(y)^2z

设sin (x+2y-3z)=x+2y-3z，证明sin (x+2y-3z)=x+2y-3z.设，证明.

(x,y,z)=(x)^3+4(y)^3+4(z)^2，则(x,y,z)=(x)^3+4(y)^3+4(z)^2（）。(x,y,z)=(x)^3+4(y)^3+

2x+3y+Z=4X-2y+4z=-5(2)3x+8y-2z=134x-y+9z=-62x+3y+Z=4X-2y+4z=-5(2)3x+8y-2z=134x-y

设(x,y,z)=(x)^2+(y)^3+z,求(x,y,z)=(x)^2+(y)^3+z,在点(x,y,z)=(x)^2+(y)^3+z,处沿方向(x,y,z