设总体 $X \sim N(\mu,4)$,$(X_1,X_2,\cdots;X_n)$ 是总体 $X$ 的样本,令 $\overline{X}=\frac{1}{n}\sum_{i=1}^{n}X_i$,则 $\mu$ 的置信水平为 $1-\alpha$ 的置信区间为().
A)$\left(\overline{X}-u_{\frac{\alpha}{2}}\frac{4}{\sqrt{n}},\overline{X}+u_{\frac{\alpha}{2}}\frac{4}{\sqrt{n}}\right)$
B)$\left(\overline{X}-u_{\frac{\alpha}{2}}\frac{2}{\sqrt{n}},\overline{X}+u_{\frac{\alpha}{2}}\frac{2}{\sqrt{n}}\right)$
C)$\left(\overline{X}-u_{\alpha}\frac{4}{\sqrt{n}},\overline{X}+u_{\alpha}\frac{4}{\sqrt{n}}\right)$
D)$\left(\overline{X}-u_{\alpha}\frac{2}{\sqrt{n}},\overline{X}+u_{\alpha}\frac{2}{\sqrt{n}}\right)$
A)(overline(X) - u_(alpha) (2)/(sqrt(n)), overline(X) + u_(alpha) (2)/(sqrt(n))
(D) (overline (x)-(u)_(a12)dfrac (2)(sqrt {n)},overline (x)+(u)_(a12)dfrac (2)(s
(B) dfrac (sqrt {n)(overline (X)-mu )}(S)sim t(n-1).-|||-(C) dfrac (sqrt {n)(ove
一维线性谐振子处在基态 psi (x)=sqrt (alpha /sqrt {pi )}(e)^-dfrac (1{2)(a)^2(x)^2} ,求-|||-(
X_n)是来自总体N(mu,sigma^2)的样本,overline(X)为样本均值,S^2为样本方差,则(overline(X)-mu)/(S/sqrt(n)
设随机变量X~N(μ,σ2),Y~χ2(n),且相互独立,记统计量T=sqrt(n)(overline(X)-μ)/(σsqrt(Y)),则( )A. T服从t
(B) (n-1)(S)^2+(overline {X)}^2 (C) (S)^2+(overline {X)}^2. (D) dfrac (n-1)(n)(S
设总体 X 服从正态分布 N(0, sigma^2),overline(X), S^2 分别是容量为 n 的样本的均值和方差,则 (sqrt(n)overlin
设总体 X 服从正态分布 N(0, sigma^2),overline(X),S^2 分别是容量为 n 的样本的均值和方差,则 (sqrt(n)overline
(sigma )_(n)=sqrt (dfrac {pi (1-pi ))(n)}-|||-C. (sigma )_(overline {x)}=dfrac (