一.化简overline (AB)cup C)(overline (AC))一.化简
化简:overrightarrow((overline{AB) cup C) (overline(AC))} 化简:$\overrightarrow{(\ove
(1,2)cup (2,3] C.[1,3) D. [ 1,2)cup (2,3)
[题目]证明 cup (Bcap C)=(Acup B)cap (Acup C)
[ sqrt (3),2] -|||-C. [ -2,-sqrt (3)] D. [ -2,-sqrt (3)] cup [ sqrt (3),2]
(0,1)cup (1,4] D. (0,1)cup (1,4)
=AB+overline (AC)+overline (BC)+overline (C)D+overline (D) __-|||-__ __
3.13计算 cup B cap B -B oplus B.-|||-(1) = a,b ,c} = c,d .-|||-(2) = a,{ b , c,(c
(1)(overline(AB)cup C)(overline(AC)); (2)(Acup B)(Acupoverline(B)).6.证明:(Acup B
C 若 AB = O ,则 B = O ; D 若 AC = BC ,则 A = B ;若A,B,C均为同阶方阵,且A可逆,则下列结论成立的是()A若AB=CB