已知(x,y)=(e)^x+(y-2)arcsin sqrt ({x)^2+(y)^2}，求(x,y)=(e)^x+(y-2)arcsin sqrt ({x)^
20.[已知平面有界区域D=(x,y)mid x^2+y^2leq 4x,x^2+y^2leq 4y计算iintlimits_(D)(x-y)^2dxdy.20
6 已知平面区域D=((x,y)|sqrt(1-y^2)le xle 1,-1le yle 1),计算iintlimits_(D)(x)/(sqrt(x^2)+
设区域 :(x)^2+(y)^2leqslant 1, 计算 =(iint )_(D)[ sin (x)^2cos (y)^2+sin (x-y)dxdy]
(5)已知积分区域 = (x,y)||x|+|y|leqslant dfrac {pi )(2)} _(1)=iint sqrt ({x)^2+(y)^2}d
18.设 = (x,y)|0leqslant yleqslant sqrt {4-{x)^2}} , 计算二重积分-|||-iint ((x)^2+(y)^2+
已知平面有界区域D=(x,y)mid x^2+y^2leq 4x,x^2+y^2leq 4y，计算二重积分iintlimits_(D)(x-y)^2dxdy.(
证明u(x,y)=(x-y)(x^2+4 xy+y^2)u(x,y)=(x-y)(x^2+4 xy+y^2)u(x,y)=(x-y)(x^2+4 xy+y^2)
2、计算 =iint ((x)^2+(y)^2+2y)dxdy, 其中D是由圆 ^2+(y)^2=2x 围成的平面区域。
10.设f(x,y)=}x-y+1,x+yleqslant1, (1)/(sqrt(x^2)+y^(2)),x+y>1,.计算I=iintlimits_(D)f