.计算下列积分:-|||-(12)f(x)dx,其中 f(x)= {x)^2,xgt 1 .
求定积分:∫(;)_(0)^2f(x)dx,其中f(x)={x+1,x≤1)(1)/(2){x)^2,x>1}..求定积分:∫${\;}_{0}^{2}$f(x
[题目]设连续函数f(x)满足 (x)=(x)^2-(int )_(0)^2f(x)dx ,则-|||-(int )_(0)^2f(x)dx=
设 f(2)=4 , (int )_(0)^2f(x)dx=1, 则 (int )_(0)^2xf(x)dx=
计算下列定积分。-|||-(int )_(0)^1x(e)^-dfrac ({x^2)(2)}dx
[题目]已知 (x)=(x)^2+(int )_(0)^2f(x)dx, 则∫f-|||-(x) = __ .
已知 (x)cdot (int )_(0)^2f(x)dx=8, 且 (0)=0, (x)geqslant 0, 则 f(x)= __
3.已知 (int )_(0)^2f(x)dx=3 ,则 (int )_(0)^2[ f(x)+6] dx= __ 一
计算下列定积分。-|||-(int )_(0)^1dfrac ({x)^4}(1+{x)^2}dx
【例4】已知函数f(x)在[-1,2]上连续,且int_(-1)^0f(x)dx=2,int_(0)^1f(2x)dx=1,则int_(-1)^2f(x)dx=