16.设 = (x,y)|{x)^2+(y)^2leqslant x} ,求 iint sqrt (x)dxdy -

.用极坐标计算下列二重积分:-|||-iint sin sqrt ({x)^2+(y)^2}dxdy ,其中 = (x,y)|{m)^2leqslant (x)

4.设 iint sqrt ({a)^2-(x)^2-(y)^2}dxdy=dfrac (16)(3)pi , 其中 :(x)^2+(y)^2leqslant

设区域 :(x)^2+(y)^2leqslant 1, 计算 =(iint )_(D)[ sin (x)^2cos (y)^2+sin (x-y)dxdy]

9.设平面区域 = (x,y)|{x)^2+(y)^2leqslant 1} , 则 iint ((x)^2+(y)^2)dsigma = __

20.计算 iint arctan (dfrac (y)(x))dxdy, 其中 = (x,y)|1leqslant {x)^2+(y)^2leqslant 4

(5)已知积分区域 = (x,y)||x|+|y|leqslant dfrac {pi )(2)} _(1)=iint sqrt ({x)^2+(y)^2}d

6.用适当的变换计算下列二重积分:-|||-(1) iint sqrt ({x)^2+(y)^2}dxdy = (x,y)|{x)^2+(y)^2leqslan

(10)设域 :(x)^2+(y)^2leqslant 1, f是域D上的连续函数,则 iint int (sqrt ({x)^2+(y)^2})dxdy= (

设D: leqslant (x)^2+(y)^2, =dfrac (dxdy)(sqrt {{x)^2+(y)^2}}=()leqslant yleqslant

[题目]-|||-_(1)=iint ((x+y))^3dxdy,(I)_(2)=iint ((x+y))^2dxdy, 其中 :((x-2))^2+((y-1