$\lim_{x \to 0} \frac{(1+x)^{\frac{2}{x}} - e^2}{x}$
【例2】lim_(xto0)((1+x)^frac(1)/(x)-e)(x)=_.【例2】$\lim_{x\to0}\frac{\left(1+x\right)
极限 lim_(x arrow 0) ( (2 + e^frac(1)/(x))(1 + e^(2)/(x)) + (sin x)/(|ln(1+x)|) )
(Ⅳ)lim_(xto0)((1+x)^frac(3)/(x)-e^3)(x);(Ⅳ)$\lim_{x\to0}\frac{\left(1+x\right)^{
11.已知lim_(x to 0) (ln(1+frac(f(x))/(x)))(2^x-1)=3,则lim_(x to 0) (f(x))/(sqrt(1+x
lim_(x to +infty) ((1+frac(1)/(x))^x^2)(e^x) $\lim_{x \to +\infty} \frac{\left(1
lim_(xto0)(1+x^2)^(1)/(sin^(2)x)=()A. eB. -eC. $e^{-1}$D. 1
求极限 lim_(x arrow 0) (3sin x+x^2cos frac1x)/((1+cos x)ln(1+x))求极限$ \lim_{x \right
lim_(x arrow infty ) ((1+x)/(x))^2x$\lim_{x \rightarrow \infty } (\frac{1+x}{x})
②lim_(xto+infty)(1+x)^(1)/(x).③lim_(xtoinfty)(1+(1)/(sqrt(1+x^2)))^x. ④lim_(xto
(3) (2009-3) lim_(x arrow 0) (e-e^cos x)/(sqrt[3](1+x^2)-1)(3) (2009-3) $\lim_{x