[题目]设连续函数f(x)满足 (x)=(x)^2-(int )_(0)^2f(x)dx ,则-|||-(int )_(0)^2f(x)dx=
设 f(2)=4 , (int )_(0)^2f(x)dx=1, 则 (int )_(0)^2xf(x)dx=
[2023年真题]设连续函数f(x)满足: f(x+2)-f(x)=x,int_(0)^2f(x)dx=0,则 int_(1)^3f(x)dx=[2023年真题
[单选题]满足方程f(x)+2f(x)dx=x2的解f(x)是:()A . -(1/2)e-2x+x+1/2B . (1/2)e-2x+x-1/2C . ce-2x+x-1/2D . ce-2x+x+1/2
求定积分:∫(;)_(0)^2f(x)dx,其中f(x)={x+1,x≤1)(1)/(2){x)^2,x>1}..求定积分:∫${\;}_{0}^{2}$f(x
[例26]已知 (dfrac (x+1)(x-1))=2f(x)-3x, 则 f(x)= __
14.设 f(x)= ^x) xlt 0 dfrac (1)(1+x) xgeqslant 0f(x-1)dx
(11)设(x-1)=(e)^2x-x+1-|||-__,则 f ( x ) =___________(12)设 (x-1)=(e)^2x-x+1-|||-__
设(x)+(x)^2f(dfrac (1)(x))=dfrac ({x)^2+2x}(x+1) 求f(x)设
[题目]已知 (x)=(x)^2+(int )_(0)^2f(x)dx, 则∫f-|||-(x) = __ .