A. 2
B. 1
C. 0
D. 3
已知随机变量X,Y相互独立,且E(X)=2,E(Y)=3,则X,Y的协方差Cov(X,Y)= 。A. 0B. 1C. 5D. 6
下列关于协方差的概念与性质正确的是A cov ( X , Y ) = -cov ( Y , X ) B cov ( X , Y ) = E ( XY ) + E
两随机变量X,Y的协方差定义为:cov(X,Y)=E(XY)-E(X)E(Y).(1)证明:D(X+Y)=D(X)+D(Y)+2cov(X,Y).(2)若X,Y
[单选题]设X,Y为随机变量,E(X)=E(Y)=1,Cov(X,Y)=2,则E(2XY)=( )A.-6B.-2C.2D.6
,-|||-求E(X),E(Y ),Cov(X,Y),ρ XY` D(X+Y)
, leqslant xleqslant 2, leqslant yleqslant 2,-|||-其他.-|||-E(X),E(Y),Cov(X,Y),ρ x
设sim pi (4) sim b(9,0.2),且E(XY)=8,则X,Y的协方差Cov(X,Y)=_______设,且E(XY)=8,则X,Y的协方差Cov
判断:若E [ (X-E(X))(Y-E(Y))] =0,则E [ (X-E(X))(Y-E(Y))] =0的协方差为E [ (X-E(X))(Y-E(Y))]
[单选题]设(X,Y)为二维随机变量,且Cov(X,Y)=-0.5,E(XY)=-0.3,E(X)=1,则E(Y)=( )A.-1B.0C.0.2D.0.4
[问答题]设E(X)=1,E(Y)=2,D(X)=1,D(Y)=4,ρXY=0.6,则E(2X-Y+1)2=-----------.