(D) dfrac ((n-1){S)^2}({sigma )^2}sim (chi )^2(n)

=dfrac (1)({X)^2}, 则()-|||-A、 sim (chi )^2(n) B、 sim (chi )^2(n-1) C、 sim F(n,1)

A)(S^2)/(sigma^2) sim chi^2(n-1) B)(n(overline(X)-mu)^2)/(S^2) sim F(1, n-1)

X_(n)是来自总体N(mu,sigma^2)的样本，overline(X),S^2分别是样本均值和样本方差，则((n-1)S^2)/(sigma^2)sim

({S)_(n)}^2=dfrac (1)(n-1)sum _(i=1)^n((x)_(i)--|||-(x))^2 是样本方差,试求满足 (dfrac ({{

(sim N(mu ,(sigma )^2),sim N(mu ,(sigma )^2),sim N(mu ,(sigma )^2),sim N(mu ,(si

(B) (n-1)(S)^2+(overline {X)}^2 (C) (S)^2+(overline {X)}^2. (D) dfrac (n-1)(n)(S

设 X_1, X_2, ldots, X_n 是来自正态总体 X sim N(mu, sigma^2) 的样本，则 ((n-1)S^2)/(sigma^2) s

设总体X sim N(0, sigma^2), X_1, X_2,..., X_n为来自X的样本，则服从chi^2(n-1)的是A. $\sum_{i=1}^n

3 设随机变量 -t(n) (ngt 1) =dfrac (1)({T)^2}, 则-|||-(A) sim (X)^2(n) (B) sim (X)^2(n

X_n 和 Y_1 ... Y_n 分别取自正态总体 X sim N(mu_1, sigma^2) 和 Y sim N(mu_2, sigma^2), 且 X